As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.

Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

**Q1.**“Pascal-Second” has dimension of

(d) NSm

^{-2}=Nm

^{-2}×S= Pascal-second

**Q2.**In the equation X=3YZ

^{2}, X and Z have dimensions of capacitance and magnetic induction respectively. In MKSQ system, the dimensional formula of Y is

(d) [capacitance X]=[M

^{-1}L

^{-1}T

^{2}Q

^{2}] [Magnetic induction Z] = [MT

^{-1}Q

^{-1}] [Z

^{2}]=[M

^{2}T

^{-2}Q

^{-2}] Given, X=3YZ

^{2}or Y=X/(3Z

^{2}) or [Y]=([X])/[Z]

^{2}∴ [Y] =([M

^{-1}L

^{-2}T

^{2}Q

^{2}])/([M

^{2}T

^{-2}Q

^{-2}])=[M

^{-3}L

^{-2}T

^{4}Q

^{4}]

**Q3.**The dimensional formula for impulse is same as the dimensional formula for

(a) Momentum = mv=[MLT

^{-1}] Impulse = Force × Time = [MLT

^{-2})]×[T]=[MLT

^{-1}]

**Q4.**If E,M,L and G denote energy, mass, angular momentum and gravitational constant respectively, then the quantity (EL

^{2}/M

^{5}G

^{2}) has the dimensions of

(a) [E]=[ML

^{2}T

^{-2}] [M]=[M] [L]=[ML

^{2}T

^{-1}] [G]=[M

^{-1}L

^{3}T

^{-2}] [(EL

^{2})/(M

^{5}G

^{2})]=([ML

^{2}T

^{-2}] [ML

^{2}T

^{-1}]

^{2})/([M]

^{5}[M

^{-1}L

^{3}T

^{-2}]

^{2}) =([ML

^{2}T

^{-2}][M

^{2}L

^{4}T

^{-2}])/([M

^{5}][M

^{-2}L

^{6}T

^{-4}])=([M

^{3}L

^{6}T

^{-4}])/([M〗

^{3}L

^{6}T

^{-4}]) =[m

^{0}L

^{0}T

^{0}]= Angle

**Q5.**Unit of electric flux is

(a) If E is the intensity of electric field over a small area element dS and θ is angle between E and outdrawn normal to area element. Therefore, electric flux through this element is dϕ

_{E}=(dS)(E cosθ ) =E dS cosθ=E.dS Hence,ϕ

_{E}=E .S = V/d .S ∴Unit of ϕ

_{E}=(volt ×metre

^{2})/metre =volt-metre

**Q6.**Dimensions of frequency are

(b) Frequency = 1/T=[M

^{0}L

^{0}T

^{-1}]

**Q7.**Students I, II and III perform an experiment for measuring the acceleration due to gravity (g) using a simple pendulum. They use different lengths of the pendulum and/or record time for different number of oscillations. The observations are shown in the table Least count for length =0.1 cm Least count for time =0.1 s

If E

_{I},E

_{II}and E

_{III}are the percentage errors in g,i.e.,(∆g/g×100) for students I, II and III, respectively

(b) % error in g=∆g/g×100=(∆l/l)×100+2(∆T/T)×100 E

_{I}=0.1/64×100+2(0.1/128)×100=0.3125% E

_{II}=0.1/64×100+2(0.1/64)×100=0.4687% E

_{III}=0.1/20×100+2(0.1/36)×100=1.055%

**Q8.**The unit of the coefficient of viscosity in S.I. system is

d) [η]=ML

^{-1}T

^{-1}so its unit will be kg/m-sec

**Q9.**The physical quantity angular momentum has the same dimensions as that of

(d) Angular momentum, [J]=[Iω]=[ML

^{2}T

^{-1}] Planck’s constant, [h]=[E]/[v] =[ML

^{2}T

^{-1}]

**Q10.**The physical quantity having the dimensions [M

^{-1}L

^{-3}A

^{2}] is

c) Resistivity, ρ=m/(ne^2 τ) ∴[ρ]=[M]/[L

^{-3}][AT][T^2 ] =[ML

^{3}A

^{-2}T

^{-3}] So, electrical conductivity σ=1/ρ ⇒ [σ]=1/[ρ] =[M

^{-1}L

^{-3}A

^{2}T

^{3}]